First-Order Reaction Half-Life Calculator
Calculate the half-life and concentration over time for 0th, 1st, and 2nd order chemical reactions.
Find time to reach any percentage of original concentration.
How Chemical Half-Life Is Calculated
Half-life is the time required for the concentration of a substance to decrease to half its initial value. It applies to radioactive decay, drug metabolism, and first-order chemical reactions.
First-Order Half-Life Formula:
t(1/2) = ln(2) / k = 0.693 / k
Where:
- t(1/2) = half-life (any time unit)
- k = rate constant (same time unit, s⁻¹, min⁻¹, hr⁻¹, etc.)
- ln(2) = natural log of 2 ≈ 0.6931
Remaining Concentration Formula:
C(t) = C₀ × (0.5)^(t / t(1/2))
Or equivalently: C(t) = C₀ × e^(−kt)
Worked Example: A pesticide with a half-life of 14 days is applied at 500 mg/kg soil. How much remains after 42 days?
- Number of half-lives = 42 / 14 = 3
- C(42) = 500 × (0.5)³ = 500 × 0.125 = 62.5 mg/kg
Half-Life Reference Values:
- Caffeine in bloodstream: ~5 hours
- Aspirin: ~3–4 hours
- Diazepam (Valium): 20–70 hours
- DDT in soil: ~2–15 years
- Carbon-14 (radioactive): 5,730 years
- Plutonium-239: 24,100 years
After Multiple Half-Lives:
- 1 half-life: 50% remains
- 5 half-lives: ~3.1% remains (often considered “cleared” in pharmacology)
- 10 half-lives: ~0.1% remains
Second-Order Reactions: Not all substances follow first-order kinetics. For second-order reactions, half-life depends on the initial concentration: t(1/2) = 1 / (k × C₀). This means the half-life changes as the reaction proceeds — a key distinction from radioactive decay, which is always first-order.